**Solution:**

We first obtain the Thevenin equivalent.

and

Note that this is not a desirable Q-point location since V_{BB} is very close to V_{BE}. Variation in V_{BE} therefore significantly change I_{C}.We find R_{ac} = R_{C} || R_{load}= 500 W and R_{dc} = R_{C} + R_{E} =1.1KW. The value of V_{CE} representing the quiescent value associated with I_{CQ} is found as follows,

Then

Since the Q-point is on the lower half of the ac load line, the maximum possible symmetrical output voltage swing is

The ac power output can be calculated as

The power drawn from the dc source is given by

The power loss in the transistor is given by

The Q-point in this example is not in the middle of the load line so that output swing is not as great as possible. However, if the input signal is small and maximum output is not required, a small I_{C} can be used to reduce the power dissipated in the circuit.

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